Markdown - Others

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x2 produces x2
x2 produces x2




Often makes no sense.

Commenting above your quote…

Traversy Media

Traversy Media

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link text

Text1 will link to the first link, and Text2 to the second. You can reuse names, and give longer names like this one. You can also link text like this without giving the reference an explicit name.

  • Item 1
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  • Item 3
    • Nested Item 1
    • Nested Item 2
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    • Nested Item 1
    • Nested Item 2
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  1. Item 1
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Duck
Same Duck

Write Code Here

code containing a backtick ( ) character `

  npm install
  npm start
  function add(num1, num2) {
      return num1 + num2;
  }
  def add(num1, num2):
    return num1 + num2
Name Email
John Doe john@gmail.com
Jane Doe jane@gmail.com
Column Column Column
Left Center Right
align align align
  • Task 1
  • Task 2
  • Task 3

* Escape character

! This is hidden until your cursor hovers on top of it

Writing Math

To write formulas using the inline mode, they should be surrounded by a single $, displayed mode, they should be surrounded by a $$

Greek Letters

Symbol Command
$\alpha$ $\alpha$
$\beta$ $\beta$
$\gamma$ $\gamma$
$\Gamma$ $\Gamma$
$\pi$ $\pi$

Usual functions and operators

Symbol Command
$\cos$ $\cos$
$\sin$ $\sin$
$\lim$ $\lim$
$\exp$ $\exp$
$\to$ $\to$
$\in$ $\in$
$\forall$ $\forall$
$\exists$ $\exists$
$\equiv$ $\equiv$
$\sim$ $\sim$
$\approx$ $\approx$
$\times$ $\times$
$\le$ $\le$
$\ge$ $\ge$

Exponents and indices

Symbol Command
$k_{n+1}$ $k_{n+1}$
$n^2$ $n^2$
$k_n^2$ $k_n^2$

Fractions, binomial coefficients, square roots

Symbol Command
$\frac{4z^3}{16}$ $\frac{4z^3}{16}$
$\frac{n!}{k!(n-k)!}$ $\frac{n!}{k!(n-k)!}$
$\binom{n}{k}$ $\binom{n}{k}$
$\frac{\frac{x}{1}}{x - y}$ $\frac{\frac{x}{1}}{x - y}$
$^3/_7$ $^3/_7$
$\sqrt{k}$ $\sqrt{k}$
$\sqrt[n]{k}$ $\sqrt[n]{k}$

Summations and integrals

Symbol Command
$\sum_{i=1}^{10} t_i$ $\sum_{i=1}^{10} t_i$
$\int_0^\infty \mathrm{e}^{-x}, \mathrm{d}x$ $\int_0^\infty \mathrm{e}^{-x}, \mathrm{d}x$

Outfits

Symbol Command
$\hat{a}$ $\hat{a}$
$\bar{a}$ $\bar{a}$
$\dot{a}$ $\dot{a}$
$\ddot{a}$ $\ddot{a}$
$\overrightarrow{AB}$ $\overrightarrow{AB}$
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